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SolarCalcWorks

Solar Inverter Sizing Calculator

Size an inverter from the loads that actually run together, the surge your largest motor demands, and the DC current the result will pull from your bank. That last figure is the one that sizes your battery cable and its fuse, and it is the number people most often get wrong.

  • Continuous and surge sizing
  • DC input current at real bus voltage
  • 12 V · 24 V · 48 V banks
  • Feeds the cable and fuse calculators

Solar Inverter Sizing Calculator

Inputs
Battery bank voltage
Inverter size96.45 A DC input

2,500W continuous

It will draw 96.45 A from the battery

That is the figure that sizes your battery cable and its fuse, calculated at 23.0 V — the bus voltage under load, because current peaks when the battery is lowest.

DC input current
96.45 A
at 23.0 V
During surge
192.90 A
for a few seconds
Surge needed
4,000 W
1.6× continuous
DC fuse basis
120.56 A
125 % of continuous
  • NoteContinuous load means what actually runs together. Adding up the nameplate of every appliance in a house produces an inverter two to three times larger than anybody needs, and inverters are least efficient at a small fraction of their rating.
  • NoteThe DC input current is calculated at the lowest bus voltage, because that is when current is highest — which is the condition that sizes the cable and the battery-side fuse.
Calculation

1Continuous rating

2,000 W × 1.25 = 2,500 W
next commercial size = 2,500 W

The 25 % headroom mirrors the continuous-load convention used throughout the NEC. It keeps the inverter off its ceiling, where efficiency falls and heat rises.

2DC input current

2,000 W ÷ 0.90 ÷ 23.04 V = 96.45 A

Two details people miss. The inverter draws more DC power than it delivers as AC, so efficiency divides rather than multiplies. And the bus sags under load — we use 23.0 V rather than the 24 V nominal, because the highest current happens at the lowest voltage, and that is the case the cable has to survive.

3Surge

4,000 W ÷ 0.90 ÷ 23.04 V = 192.90 A briefly

Surge sizes the inverter's peak rating, not the conductors. A conductor's thermal mass absorbs a few seconds easily, so sizing cable to surge amps buys copper you do not need. It does matter for voltage drop, because a marginal cable sags the bus exactly when a motor needs it most.

Inverter sizing is manufacturer and load driven rather than code driven; the NEC governs the conductors and protection around an inverter, not its rating. Sources and limitations.

NextSize the cable for 96.45 AThe DC input current above is exactly what that calculator needs.

Three questions, not one

Inverter sizing conflates three separate things, and separating them is what stops people buying twice the inverter they need.

Continuous is what it must sustain indefinitely: the loads that genuinely run together.

Surge is what it must survive for a few seconds while a motor starts. This sizes the inverter’s peak rating — it does not size the conductors, because a conductor’s thermal mass absorbs a few seconds easily.

DC input current is what it pulls from the battery. This is the output that feeds the rest of your design: the battery cable, the battery-side fuse, and the maximum discharge current your bank has to support.

Working out continuous load

Only what runs simultaneously:

Load Watts Runs with others?
Fridge (running) 150 Yes, cycles all day
LED lighting 60 Yes
Laptop and chargers 100 Yes
Water pump 400 Briefly, occasionally
Microwave 1200 Not with the hob
Induction hob 1800 Not with the microwave

A realistic worst case here is the fridge, lights, laptop and the hob together — around 2100 W, not the 3710 W the column adds up to. Add 25 % headroom and a 3000 W inverter covers it comfortably.

The DC side is where the money goes

I(DC) = continuous AC watts ÷ efficiency ÷ bus voltage under load

The calculator uses roughly 96 % of nominal as the default bus voltage, because current peaks when the battery is lowest and that is the case the cable has to survive. You can enter your own figure if you know the sag on your bank.

The consequence of bank voltage is dramatic:

Inverter 12 V 24 V 48 V
2000 W 185 A 93 A 46 A
3000 W 278 A 139 A 69 A
5000 W 463 A 231 A 116 A

At 12 V a 5000 W inverter needs over 460 A, which is beyond any single conductor in the NEC tables up to 500 kcmil. If you are still choosing a bank voltage, this table is the argument.

Surge, and when to solve it differently

Most inverters offer roughly 2× continuous for a few seconds. If your surge demand is much beyond that, a larger inverter is one answer and often the worst one — you pay for continuous capacity you never use, plus its idle draw, to cover a two-second event.

A soft starter on the offending load is frequently cheaper. Fitted to an air conditioner or a well pump, it limits inrush to a fraction of what the motor would otherwise demand, and it lets a correctly-sized inverter handle a load that would otherwise have forced the next size up.

What comes next

The DC input current from this calculator is the input to two other decisions: the battery cable, and the overcurrent device that protects it at the battery end. Both are sized from that number, not from the inverter’s AC rating.

Frequently asked questions

What size inverter do I need for my house or cabin?

Add up only what runs at the same time. A kettle, a microwave and an induction hob each draw 1500 W or more, but almost nobody runs all three simultaneously. Adding every nameplate in the building produces an inverter two to three times larger than anyone needs, costs more, and runs less efficiently — inverters are least efficient at a small fraction of their rating. Work out a realistic simultaneous load, add 25 %, and round up.

What is surge and why does it need a separate number?

Induction motors draw several times their running current during the first fraction of a second as they start. A fridge compressor rated 150 W running can demand 600 W or more briefly; a well pump considerably more. Inverters publish a separate surge rating, usually about twice continuous for a few seconds. Sizing on continuous watts alone produces an inverter that trips whenever the compressor cuts in.

How much current does an inverter draw from the battery?

Continuous AC watts, divided by the inverter's efficiency, divided by the battery voltage under load. The two details people miss are that efficiency divides rather than multiplies — the inverter takes more from the battery than it delivers — and that the battery sags under load, so the correct voltage is the low end of the range rather than nominal. Both push the current up, and the current is what sizes the cable.

Does a bigger inverter waste power when idle?

Yes. Inverters have a no-load or idle draw that scales roughly with their size — commonly 10 to 40 W for a mid-size unit. Left on continuously, 25 W of idle draw is 600 Wh a day, which on a small off-grid system can exceed the useful load. Many inverters have a search or power-save mode that cuts this dramatically at the cost of a short delay when a load appears.

Pure sine wave or modified sine wave?

Pure sine for anything you care about. Modified sine wave is cheaper and adequate for simple resistive loads, but it makes induction motors run hotter and less efficiently, can cause audible buzz in audio gear, and some electronics — certain medical devices, some chargers, variable-speed tools — either refuse to run or fail early. The price gap has narrowed enough that pure sine is the default choice now.

Last reviewed 2026-08-19. Calculations reference NFPA 70 (NEC) 2023 where a code section applies. Sources, and what these tools deliberately do not model.